Advanced Placement (AP), 08.10.2020 08:01 mohd591

What is widely considered to be a limitation to Piaget's cognitive theory of development? (A) It views development as distinct, age-linked stages rather than a continuous process of growth.
(B) It states that all cognitive development takes place from social learning.
(C) It describes the ability to think and reason abstractly beginning in adolescence.
(D) It focuses on attachment parenting and is not based on scientific data.

Answers: 2

Show answers

Answers

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Answer from: Quest

u all ready kno b

explanation:

Answer from: Quest

answer; they saved ancient greek and roman writings.

Answer from: Quest

answer:

explanation:

1+1 = 2

the reason this is so is because of basic addition. we can double check this without using addition if you really want. if you take 1+1=x, subtract 1 from both sides than you get 1 = x - 1. subtract x from both sides and you get 1 - x = -1. subtract 1 from both sides again and you get -x = -2. finally, multiply both sides by -1 to get x = 2. subtraction is still technically addition you say? fine, have it your way. 1 + 1 = x. by definition, adding something to itself is the same thing as multiplying it by 2. this means we can technically rewrite the equation as

1 * 2 = x. now all we have to do is solve it. 1 * 2 = x when simplified results in 2 = x, or x = 2. this shows 1 + 1 = x. you say you want a real answer. you want me to start you from the ground up? well i would, but that would practically just be stealing from what was written on this website: go check it out if you really need to.

Another question on Advanced Placement (AP)

Advanced Placement (AP), 23.06.2019 20:20

Will mark brainliest ! the two parking space configurations you'll see in garages and parking lots are a. low-angle and high-angle spaces b. high-angle and boxed spaces c. straight-in spaces and angle spaces d. left-angle spaces and herringbone spaces

Answers: 1

Answer

Advanced Placement (AP), 24.06.2019 02:30

How american was colonial art? to what extent does it illustrate the development of a new society

Answers: 1

Answer

Advanced Placement (AP), 25.06.2019 00:00

Which of the following statements concerning the effects of happiness is not true? select the best answer from the choices provided feelings of happiness generally lead individuals to demonstrate less care toward others. happy individuals are generally more playful than individuals who are not. research has linked levels of happiness to increases in creative problem solving. happiness, along with love, has been found to provoke prosocial behaviors.

Answers: 1

Answer

Advanced Placement (AP), 25.06.2019 06:30

You are only allowed to use tutors that your school recommends. t / f

Answers: 2

Answer

You know the right answer?

What is widely considered to be a limitation to Piaget's cognitive theory of development? (A) It vi...

Questions