On a coordinate plane, line M N goes through (negative 4, 0) and (4, 2). Point P is at (2, negative 4). Which point on the x-axis lies on the line that passes through point P and is perpendicular to line MN? (0, 1) (0, 4) (1, 0) (4, 0)

C, (1,0)

Explanation:

A perpendicular line is when 2 lines cross each other with right angles, which are 90⁰ angles. Two lines are only perpendicular when the lines slopes are negative reciprocals to each other.

To find the slope of the first graph use, (y2-y1)/(x2-x1)

This is, 2-0/4+4

2/8

1/4 is the slope for the first line.

The negative reciprocal of this is -4.

We are also looking for a point on the x axis, so this eliminates answer choice A, and B, because they aren't even on the x axis.

When you test out answer choice c it will show that,

-4-0/2-1=-4/1 which is just -4.

These points on line p will pass each other when you add +4, y=-4x+4. So because of both of these lines negative reciprocating slopes, it shows that it will be answer C.

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