Find the real zeros of a trigonometric function Interval : sin theta -4/5, 3pi/2 < theta < 2pi Find tan(2theta)
a.24/7
b 7/24
c -24/7
d -7/24

The answer to this question will be d

To solve this integral, what you can do is split it up as follows: (1) ∫40(x2−4)dx=∫40(x2)dx−∫40(4)dx. to integrate  4  as an  indefinite integral, a good rule of thumb is  by  an equation below  for  polynomials; . (2) ∫xa=xa+1a+1+c , where a is any number. c denotes some constant that is crucial when doing 

What is this supossed to be?