Limit as x approaches 0 of (2e^x-2)/x

Explanation:

So first, we have to plug in zero and see if we can evaluate this limit simply from that.

When we plug in zero we get: (2e^0-2)/0

e^0 is 1 so we have 2-2/0 or 0/0. So we have an indeterminate form type 0/0.

This means we have to apply L'Hospital's Rule.

As a reminder L'Hospitals Rule is

Meaning that we take the derivative of the top and bottom function as the approach some value "c". We can do this with a 0/0 indeterminate form.

So:

The derivative of 2e^x - 2 is just 2e^x

and the derivative of x is 1

So we are left with

Plugging in zero we see this gives us 2 as 2(e^0) = 2(1) = 2.

Hence, = 2

i don't know the answer

no neither are correct. you can find the answer on page 2.2, under the heading "enunciation and pronunciation"

stating:

"enunciation is the way you form your words when you speak. pronunciation is how you say each syllable."

pf

i dont care who you give brailiest to. its up to you

but nice try to the other answer

close

but dont give me brailiest