4select the correct answer. a bumper car with a mass of 200 kilograms traveling at a velocity of 3.5 meters/second collides with a stationary bumper car with a mass of 250 kilograms. if the two bumper cars stick and move together at a velocity of 2.3 meters/second, what is the kinetic energy of the system after the collision?

ek = (m·v2) / 2

v - velocity of system after the collision

m = m1 + m2

ek = (m1 + m2) ·v2/2

ek = (200 + 250) ·2,32/2 = 450·5,29/2 = 1190,25 j

ek = (m.v2) / 2

v - velocity of system after the collision

m = m1 + m2

ek = (m1 + m2) v2/2

ek = (200 + 250) 2,32/2 = 450*5,29/2 = 1190,25 j

by: nicholas dooley

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